LeetCode 136: Single Number | Optimized Java Solution (Bit Manipulation)
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Swastik | DSA | Development on Instagram: "Single Number Problem explained using XOR 🧠 LeetCode 136 | DSA Interview Question Is array me har number 2 baar aata hai, sirf ek number unique hota hai. Is reel me maine XOR trick se O(n) time aur O(1) space me solution explain kiya hai 🔥 Agar DSA, LeetCode aur placement preparation kar rahe ho, ye problem must-know hai 💯 👇 Comment “XOR” agar logic samajh aaya 📌 Save karo for revision ➡️ Follow for daily DSA & LeetCode reels"
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Swastik | DSA | Development on Instagram: "Single Number Problem explained using XOR 🧠 LeetCode 136 | DSA Interview Question Is array me har number 2 baar aata hai, sirf ek number unique hota hai. Is reel me maine XOR trick se O(n) time aur O(1) space me solution explain kiya hai 🔥 Agar DSA, LeetCode aur placement preparation kar rahe ho, ye problem must-know hai 💯 👇 Comment “XOR” agar logic samajh aaya 📌 Save karo for revision ➡️ Follow for daily DSA & LeetCode reels"
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Instagramcodewithswastikk
Sathwik bhat on Instagram: "Day 12/30 - LeetCode 136: Single Number 🎯 XOR magic unlocks O(1) space solution! ⚡ The approach: XOR all elements together Duplicates cancel out (a ⊕ a = 0) Single number remains (a ⊕ 0 = a) One pass, constant space! Time: O(n), Space: O(1) 🔥 XOR Basics (brushing up!): Same bits → 0 (1⊕1=0, 0⊕0=0) Different bits → 1 (1⊕0=1) a ⊕ a = 0 (self-canceling) a ⊕ 0 = a (identity property) Order doesn't matter (commutative) No HashSet needed—bit manipulation FTW 🧠 Drop "DAY
2:21
Sathwik bhat on Instagram: "Day 12/30 - LeetCode 136: Single Number 🎯 XOR magic unlocks O(1) space solution! ⚡ The approach: XOR all elements together Duplicates cancel out (a ⊕ a = 0) Single number remains (a ⊕ 0 = a) One pass, constant space! Time: O(n), Space: O(1) 🔥 XOR Basics (brushing up!): Same bits → 0 (1⊕1=0, 0⊕0=0) Different bits → 1 (1⊕0=1) a ⊕ a = 0 (self-canceling) a ⊕ 0 = a (identity property) Order doesn't matter (commutative) No HashSet needed—bit manipulation FTW 🧠 Drop "DAY
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